A solid sphere rolls without slipping on a horizontal surface. The fraction of its total kinetic energy that is rotational is
A. \(\frac{2}{5}\)
B. \(\frac{2}{7}\)
C. \(\frac{5}{7}\)
D. \(\frac{1}{3}\)
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Answer: B. \(\frac{2}{7}\)
\(KE_{rot}=\frac12\cdot\frac25 mR^2\omega^2=\frac15 mv^2\), \(KE_{total}=\frac12mv^2+\frac15mv^2=\frac{7}{10}mv^2\). Fraction \(=\frac{1/5}{7/10}=\frac27\).
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· 23 Oct 2026
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