In \(\triangle ABC\), seg \(DE \parallel\) side \(BC\), with D on AB and E on AC. If \(\frac{AD}{DB} = \frac{2}{3}\) and \(AE = 4\), then \(EC = \)

A. 6

B. 2.67

C. 8

D. 5

Doubtly AI Asked 24 Oct 2026 AI-verified · Oct 2026 ssc 10th Save WhatsApp Report

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Answer: A. 6

By the basic proportionality theorem, \(\frac{AE}{EC} = \frac{2}{3} \Rightarrow EC = \frac{3 \times 4}{2} = 6\).

Doubtly AI · 24 Oct 2026 AI-verified · Oct 2026 Report

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