In cyclic quadrilateral ABCD, \(\angle B = 110°\). Then \(\angle D = \)
A. 110°
B. 250°
C. 90°
D. 70°
A. 110°
B. 250°
C. 90°
D. 70°
Best answer
Answer: D. 70°
Opposite angles of a cyclic quadrilateral are supplementary: \(180° - 110° = 70°\).
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