From the top of a tower 50 m high, the angle of depression of a car on the ground is 45°. The distance of the car from the foot of the tower is
A. 50 m
B. \(50\sqrt{3}\) m
C. \(\frac{50}{\sqrt{3}}\) m
D. 100 m
A. 50 m
B. \(50\sqrt{3}\) m
C. \(\frac{50}{\sqrt{3}}\) m
D. 100 m
Best answer
Answer: A. 50 m
\(\tan 45° = \frac{50}{d} = 1 \Rightarrow d = 50\) m.
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