Answer: Manish is 23 years old and Savita is 8 years old
Let Manish's present age be \(x\) years and Savita's \(y\) years.
\(x + y = 31\) ... (I)
Three years ago: \(x - 3 = 4(y - 3)\), so \(x - 4y = -9\) ... (II)
Subtract (II) from (I): \(5y = 40\), \(y = 8\). Then \(x = 31 - 8 = 23\).
Check: 3 years ago Manish was 20 and Savita was 5, and \(20 = 4 \times 5\).