Answer: \(y^2 + 2y - 10 = 0\); \(a = 1, b = 2, c = -10\)
Given: \(2y = 10 - y^2\).
Take all terms to the left: \(y^2 + 2y - 10 = 0\).
Comparing with \(ax^2 + bx + c = 0\): \(a = 1\), \(b = 2\), \(c = -10\).
Answer: \(y^2 + 2y - 10 = 0\); \(a = 1, b = 2, c = -10\)
Given: \(2y = 10 - y^2\).
Take all terms to the left: \(y^2 + 2y - 10 = 0\).
Comparing with \(ax^2 + bx + c = 0\): \(a = 1\), \(b = 2\), \(c = -10\).
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