Answer: \(x^2 - 4x - 2 = 0\); \(a = 1, b = -4, c = -2\)
Given: \((x - 1)^2 = 2x + 3\).
\(x^2 - 2x + 1 = 2x + 3\), so \(x^2 - 4x - 2 = 0\).
Comparing with \(ax^2 + bx + c = 0\): \(a = 1\), \(b = -4\), \(c = -2\).
Answer: \(x^2 - 4x - 2 = 0\); \(a = 1, b = -4, c = -2\)
Given: \((x - 1)^2 = 2x + 3\).
\(x^2 - 2x + 1 = 2x + 3\), so \(x^2 - 4x - 2 = 0\).
Comparing with \(ax^2 + bx + c = 0\): \(a = 1\), \(b = -4\), \(c = -2\).
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