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One of the roots of equation 5m^2 + 2m + k = 0 is -7/5. Complete the following activity to find the value of k.

One of the roots of equation \(5m^2 + 2m + k = 0\) is \(\frac{-7}{5}\). Complete the following activity to find the value of \(k\).

Solution: \(\square\) is a root of quadratic equation \(5m^2 + 2m + k = 0\). ∴ Put \(m = \square\) in the equation. \(5\times\square^2 + 2\times\square + k = 0\); \(\square + \square + k = 0\); \(\square + k = 0\); \(k = \square\)

1 answer

Answer: \(k = -7\)

\(-\frac{7}{5}\) is a root, so put \(m = -\frac{7}{5}\):

\[5\left(-\frac{7}{5}\right)^2 + 2\left(-\frac{7}{5}\right) + k = 0\]\[\frac{49}{5} - \frac{14}{5} + k = 0\]\[7 + k = 0\]\[k = -7\]

Boxes in order: \(-\frac{7}{5}\), \(-\frac{7}{5}\), \(-\frac{7}{5}\), \(-\frac{7}{5}\), \(\frac{49}{5}\), \(-\frac{14}{5}\), 7, −7.

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