Answer: \(y = -13 \text{ or } y = -\frac{1}{2}\)
Product \(2\times 13 = 26\), sum 27: use 26 and 1.
\[2y^2 + 26y + y + 13 = 0\]\[2y(y + 13) + 1(y + 13) = 0\]\[(y + 13)(2y + 1) = 0\]Equating each factor to zero gives the roots above.
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Doubtly AI
· 24 Oct 2026
AI-verified · Oct 2026
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