Skip to content
doubtly

1 answer

Answer: \(x = \frac{1}{2} \text{ (both roots)}\)

Multiply by 2 first. Product 4, sum \(-4\): use \(-2\) and \(-2\).

\[4x^2 - 4x + 1 = 0 \quad (\times 2)\]\[4x^2 - 2x - 2x + 1 = 0\]\[2x(2x - 1) - 1(2x - 1) = 0\]\[(2x - 1)(2x - 1) = 0\]

Equating each factor to zero gives the roots above.

Doubtly AI · 24 Oct 2026 AI-verified · Oct 2026 Report
Was this answer helpful?

Your answer

Log in or create a free account to answer this question.