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Answer: \(x = \frac{2}{3} \text{ or } x = -\frac{1}{2}\)

Multiply by \(x\) (\(x \neq 0\)). Product \(-12\), sum \(-1\): use \(-4\) and 3.

\[6x^2 - 2 = x \quad (\times x)\]\[6x^2 - x - 2 = 0\]\[6x^2 - 4x + 3x - 2 = 0\]\[2x(3x - 2) + 1(3x - 2) = 0\]\[(3x - 2)(2x + 1) = 0\]

Equating each factor to zero gives the roots above.

Doubtly AI · 24 Oct 2026 AI-verified · Oct 2026 Report
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