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Solve the quadratic equation by factorisation, completing the activity: √2 x^2 + 7x + 5√2 = 0

\(\sqrt{2}x^2 + 7x + 5\sqrt{2} = 0\) to solve this quadratic equation by factorisation, complete the following activity.

Solution: \(\sqrt{2}x^2 + \square + \square + 5\sqrt{2} = 0\); \(x(\ldots) + \sqrt{2}(\ldots) = 0\); \((\ldots)(x + \sqrt{2}) = 0\); \((\ldots) = 0\) or \((x + \sqrt{2}) = 0\); ∴ \(x = \square\) or \(x = -\sqrt{2}\); ∴ \(\square\) and \(-\sqrt{2}\) are roots of the equation.

1 answer

Answer: the roots are \(-\frac{5}{\sqrt{2}}\) and \(-\sqrt{2}\)

Product of first and last coefficients \(= \sqrt{2}\times 5\sqrt{2} = 10\). Split \(7x\) as \(5x + 2x\) (since \(5\times 2 = 10\), \(5 + 2 = 7\)).

\[\sqrt{2}x^2 + 5x + 2x + 5\sqrt{2} = 0\]\[x(\sqrt{2}x + 5) + \sqrt{2}(\sqrt{2}x + 5) = 0\]\[(\sqrt{2}x + 5)(x + \sqrt{2}) = 0\]

\(\sqrt{2}x + 5 = 0\) gives \(x = -\frac{5}{\sqrt{2}}\); \(x + \sqrt{2} = 0\) gives \(x = -\sqrt{2}\).

Boxes: \(5x\), \(2x\), \(-\frac{5}{\sqrt{2}}\), \(-\frac{5}{\sqrt{2}}\).

Doubtly AI · 24 Oct 2026 AI-verified · Oct 2026 Report
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