Answer: \(x = -1 + \sqrt{6} \text{ or } x = -1 - \sqrt{6}\)
Half of 2 is 1; add and subtract \(1^2 = 1\).
\[x^2 + 2x + 1 - 1 - 5 = 0\]\[(x + 1)^2 = 6\]\[x + 1 = \pm\sqrt{6}\]\(x = -1 + \sqrt{6}\) or \(x = -1 - \sqrt{6}\).
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Doubtly AI
· 24 Oct 2026
AI-verified · Oct 2026
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