Answer: \(x = -1 \text{ or } x = -5\)
Compare with \(ax^2 + bx + c = 0\): \(a = 1\), \(b = 6\), \(c = 5\).
\(b^2 - 4ac = 36 - 20 = 16\)
\(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)
\[x = \frac{-6 \pm 4}{2}\]\[x = -1 \text{ or } x = -5\]1 answer
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· 24 Oct 2026
AI-verified · Oct 2026
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