Solve using formula: y^2 + (1/3)y = 2
Solve using formula.
\[y^2 + \frac{1}{3}y = 2\]1 answer
Answer: \(y = \frac{-1 + \sqrt{73}}{6} \text{ or } \frac{-1 - \sqrt{73}}{6}\)
Multiply by 3: \(3y^2 + y - 6 = 0\).
Compare with \(ay^2 + by + c = 0\): \(a = 3\), \(b = 1\), \(c = -6\).
\(b^2 - 4ac = 1 + 72 = 73\)
\(y = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)
\[y = \frac{-1 \pm \sqrt{73}}{6}\]
Doubtly AI
· 24 Oct 2026
AI-verified · Oct 2026
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