With the help of the flow chart given below solve the equation x² + 2√(3)x + 3 = 0 using the formula. Flow chart: compare the equation with ax² + bx + c = 0 and find a, b, c → find the value of b² - 4ac → write the formula to solve the quadratic equation → substitute values of a, b, c and find the roots.

Answer: x = -√(3) (both roots equal) Compare with ax² + bx + c = 0 : a = 1 , b = 2√(3) , c = 3 . b² - 4ac = (2√(3))² - 4(1)(3) = 12 - 12 = 0 x = -b ± √(b² - 4ac)/2a x = -2√(3) ± √(0)/2 x = -√(3) Since b² - 4ac = 0 , both roots are equal: -√(3) and -√(3) .

With the help of the flow chart given below solve the equation x^2 + 2√3 x + 3 = 0 using the formula.

With the help of the flow chart given below solve the equation \(x^2 + 2\sqrt{3}x + 3 = 0\) using the formula.

Flow chart: compare the equation with \(ax^2 + bx + c = 0\) and find \(a, b, c\) → find the value of \(b^2 - 4ac\) → write the formula to solve the quadratic equation → substitute values of \(a, b, c\) and find the roots.

Doubtly Asked 24 Oct 2026 Save WhatsApp Report

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Answer: \(x = -\sqrt{3} \text{ (both roots equal)}\)

Compare with \(ax^2 + bx + c = 0\): \(a = 1\), \(b = 2\sqrt{3}\), \(c = 3\).

\(b^2 - 4ac = (2\sqrt{3})^2 - 4(1)(3) = 12 - 12 = 0\)

\(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)

\[x = \frac{-2\sqrt{3} \pm \sqrt{0}}{2}\]\[x = -\sqrt{3}\]

Since \(b^2 - 4ac = 0\), both roots are equal: \(-\sqrt{3}\) and \(-\sqrt{3}\).

Doubtly AI · 24 Oct 2026 AI-verified · Oct 2026 Report

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With the help of the flow chart given below solve the equation x^2 + 2√3 x + 3 = 0 using the formula.

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