Answer: \(\Delta = -55\)
For \(2y^2 - 5y + 10 = 0\): \(a = 2\), \(b = -5\), \(c = 10\).
\[\Delta = b^2 - 4ac\]\[(-5)^2 - 4(2)(10) = 25 - 80 = -55\]1 answer
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· 24 Oct 2026
AI-verified · Oct 2026
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