Answer: \(\Delta = 0\)
For \(\sqrt{2}x^2 + 4x + 2\sqrt{2} = 0\): \(a = \sqrt{2}\), \(b = 4\), \(c = 2\sqrt{2}\).
\[\Delta = b^2 - 4ac\]\[4^2 - 4(\sqrt{2})(2\sqrt{2}) = 16 - 16 = 0\]1 answer
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· 24 Oct 2026
AI-verified · Oct 2026
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