The roots of the following quadratic equation are real and equal, find k: kx(x - 2) + 6 = 0

Doubtly Asked 24 Oct 2026 Save WhatsApp Report

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Answer: \(k = 6\)

\(kx^2 - 2kx + 6 = 0\), so \(a = k, b = -2k, c = 6\).

\[(-2k)^2 - 4(k)(6) = 0\]\[4k^2 - 24k = 0\]\[4k(k - 6) = 0\]

So \(k = 0\) or \(k = 6\). If \(k = 0\) the equation becomes \(6 = 0\), which is not quadratic, so \(k = 6\).

Doubtly AI · 24 Oct 2026 AI-verified · Oct 2026 Report

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