Answer: \(x = 2 + \sqrt{7}\) or \(x = 2 - \sqrt{7}\)
\(a = 1, b = -4, c = -3\); \(\Delta = 16 + 12 = 28\).
\[x = \frac{4 \pm \sqrt{28}}{2} = \frac{4 \pm 2\sqrt{7}}{2}\]\[x = 2 \pm \sqrt{7}\]1 answer
Doubtly AI
· 24 Oct 2026
AI-verified · Oct 2026
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