Answer: Yes, it is an A.P.; d = 5
Find the difference between consecutive terms:
\[132 - 127 = 137 - 132 = 5\]The difference is constant, so the sequence is an A.P.
Answer: Yes, it is an A.P.; d = 5
Find the difference between consecutive terms:
\[132 - 127 = 137 - 132 = 5\]The difference is constant, so the sequence is an A.P.
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