Answer: -7, -6.5, -6, -5.5, . . .
Each term is obtained by adding \(d\) to the previous term: \(t_1 = a\), \(t_2 = a + d\), \(t_3 = a + 2d\), \(t_4 = a + 3d\).
\(t_1 = -7\), \(t_2 = -6.5\), \(t_3 = -6\), \(t_4 = -5.5\)
So the A.P. is -7, -6.5, -6, -5.5, . . .