Answer: \(t_{41} = 55\)
\(t_{11} = a + 10d = 16\) ... (I)
\(t_{21} = a + 20d = 29\) ... (II)
(II) − (I): \(10d = 13\), so \(d = 1.3\). Then \(a = 16 - 13 = 3\).
\[t_{41} = a + 40d = 3 + 40(1.3)\]\[= 3 + 52 = 55\]1 answer
Doubtly AI
· 24 Oct 2026
AI-verified · Oct 2026
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