First term and common difference of an A.P. are 6 and 3 respectively ; find S₂₇ . a = 6, d = 3, S₂₇ = ? ; S_n = n/2[square + (n - 1)d] ; S₂₇ = 27/2[12 + (27 - 1)square] = 27/2×square = 27 × 45 = square

Answer: S₂₇ = 1215 S_n = n/2[2a + (n - 1)d] S₂₇ = 27/2[12 + 26 × 3] = 27/2 × 90 = 27 × 45 = 1215 Boxes: 2a , 3, 90, 1215.

First term and common difference of an A.P. are 6 and 3 respectively ; find S27.

First term and common difference of an A.P. are 6 and 3 respectively ; find \(S_{27}\).

\(a = 6, d = 3, S_{27} = ?\); \(S_n = \frac{n}{2}[\square + (n - 1)d]\); \(S_{27} = \frac{27}{2}[12 + (27 - 1)\square]\) \(= \frac{27}{2}\times\square\) \(= 27 \times 45 = \square\)

Doubtly Asked 24 Oct 2026 Save WhatsApp Report

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Answer: \(S_{27} = 1215\)

\[S_n = \frac{n}{2}[2a + (n - 1)d]\]\[S_{27} = \frac{27}{2}[12 + 26 \times 3]\]\[= \frac{27}{2} \times 90\]\[= 27 \times 45 = 1215\]

Boxes: \(2a\), 3, 90, 1215.

Doubtly AI · 24 Oct 2026 AI-verified · Oct 2026 Report

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First term and common difference of an A.P. are 6 and 3 respectively ; find S27.

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