In an A.P. sum of three consecutive terms is 27 and their product is 504, find the terms. (Assume that three consecutive terms in A.P. are a - d, a, a + d.)

Doubtly Asked 24 Oct 2026 Save WhatsApp Report

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Answer: 4, 9, 14 or 14, 9, 4

Sum: \((a - d) + a + (a + d) = 3a = 27\), so \(a = 9\).

\[(9 - d) \times 9 \times (9 + d) = 504\]\[81 - d^2 = 56\]\[d^2 = 25,\ d = \pm 5\]

\(d = 5\): 4, 9, 14. \(d = -5\): 14, 9, 4. Check: \(4 \times 9 \times 14 = 504\).

Doubtly AI · 24 Oct 2026 AI-verified · Oct 2026 Report

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