Answer: \(t_{10} = -1\)
\((a + 2d) + (a + 7d) = 7\), so \(2a + 9d = 7\) ... (I)
\((a + 6d) + (a + 13d) = -3\), so \(2a + 19d = -3\) ... (II)
(II) − (I): \(10d = -10\), \(d = -1\); \(2a = 16\), \(a = 8\).
\[t_{10} = 8 + 9(-1) = -1\]1 answer
Doubtly AI
· 24 Oct 2026
AI-verified · Oct 2026
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