Answer: \(n = 8\)
\[\frac{n(n + 1)}{2} = 36\]\[n^2 + n - 72 = 0\]\[(n + 9)(n - 8) = 0\]\(n\) is natural, so \(n = 8\).
Answer: \(n = 8\)
\[\frac{n(n + 1)}{2} = 36\]\[n^2 + n - 72 = 0\]\[(n + 9)(n - 8) = 0\]\(n\) is natural, so \(n = 8\).
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