Answer: (1) 1/3 (2) 2/3 (3) 2/3
n(S) = 9
(1) \( P(\text{red}) = \frac{3}{9} = \frac{1}{3} \)
(2) Not red means white or green: 6 balls. \( P = \frac{6}{9} = \frac{2}{3} \)
(3) Red or white: 6 balls. \( P = \frac{6}{9} = \frac{2}{3} \)
Answer: (1) 1/3 (2) 2/3 (3) 2/3
n(S) = 9
(1) \( P(\text{red}) = \frac{3}{9} = \frac{1}{3} \)
(2) Not red means white or green: 6 balls. \( P = \frac{6}{9} = \frac{2}{3} \)
(3) Red or white: 6 balls. \( P = \frac{6}{9} = \frac{2}{3} \)
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