If triangle ABC sim triangle PQR , A( triangle ABC) = 80, A( triangle PQR) = 125, then fill in the blanks. A(triangle ABC)/A(triangle ldots) = 80/125 , therefore AB/PQ = square/square

Answer: A(triangle ABC)/A(triangle PQR) = 80/125 = 16/25 , therefore AB/PQ = 4/5 For similar triangles, A(triangle ABC)/A(triangle PQR) = AB²/PQ² AB²/PQ² = 80/125 = 16/25 Taking square roots (lengths are positive): AB/PQ = 4/5 Blanks: PQR; 4 and 5.

If ΔABC ~ ΔPQR, A(ΔABC) = 80, A(ΔPQR) = 125, then fill in the blanks. A(ΔABC)/A(Δ....) = 80/125, therefore AB/PQ = ☐/☐

If \(\triangle ABC \sim \triangle PQR\), A(\(\triangle\)ABC) = 80, A(\(\triangle\)PQR) = 125, then fill in the blanks.

\(\dfrac{A(\triangle ABC)}{A(\triangle \ldots)} = \dfrac{80}{125}\), \(\therefore \dfrac{AB}{PQ} = \dfrac{\square}{\square}\)

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Answer: \(\dfrac{A(\triangle ABC)}{A(\triangle PQR)} = \dfrac{80}{125} = \dfrac{16}{25}\), \(\therefore \dfrac{AB}{PQ} = \dfrac{4}{5}\)

For similar triangles,

\[\frac{A(\triangle ABC)}{A(\triangle PQR)} = \frac{AB^2}{PQ^2}\] \[\frac{AB^2}{PQ^2} = \frac{80}{125} = \frac{16}{25}\]

Taking square roots (lengths are positive):

\[\frac{AB}{PQ} = \frac{4}{5}\]

Blanks: PQR; 4 and 5.

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If ΔABC ~ ΔPQR, A(ΔABC) = 80, A(ΔPQR) = 125, then fill in the blanks. A(ΔABC)/A(Δ....) = 80/125, therefore AB/PQ = ☐/☐

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