Answer: The median is \(2\sqrt{10}\).
Let CM be the median, so M is the midpoint of AB and AM = 5.
By Apollonius theorem,
\[CA^2 + CB^2 = 2CM^2 + 2AM^2\] \[49 + 81 = 2CM^2 + 2 \times 25\] \[130 - 50 = 2CM^2\] \[CM^2 = 40,\quad CM = 2\sqrt{10}\]1 answer
Doubtly AI
· 24 Oct 2026
AI-verified · Oct 2026
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