Answer: The hypotenuse is \(x\sqrt{2}\).
In an isosceles right-angled triangle, the two sides making the right angle are equal, each x. By Pythagoras theorem,
\[h^2 = x^2 + x^2 = 2x^2\] \[h = x\sqrt{2}\]Answer: The hypotenuse is \(x\sqrt{2}\).
In an isosceles right-angled triangle, the two sides making the right angle are equal, each x. By Pythagoras theorem,
\[h^2 = x^2 + x^2 = 2x^2\] \[h = x\sqrt{2}\]Log in or create a free account to answer this question.