Answer: Yes, \(\triangle PQR\) is right angled and \(\angle PRQ = 90^\circ\).
\[PQ^2 = 8,\quad QR^2 = 5,\quad PR^2 = 3\] \[QR^2 + PR^2 = 5 + 3 = 8 = PQ^2\]By the converse of Pythagoras theorem the triangle is right angled, and the right angle is opposite the longest side PQ, i.e. at vertex R: \(\angle PRQ = 90^\circ\).