Answer: AP = 7
P is the midpoint of BC, so BP = 9. By Apollonius theorem,
\[AB^2 + AC^2 = 2AP^2 + 2BP^2\] \[260 = 2AP^2 + 2 \times 81\] \[2AP^2 = 98,\quad AP^2 = 49\] \[AP = 7\]Answer: AP = 7
P is the midpoint of BC, so BP = 9. By Apollonius theorem,
\[AB^2 + AC^2 = 2AP^2 + 2BP^2\] \[260 = 2AP^2 + 2 \times 81\] \[2AP^2 = 98,\quad AP^2 = 49\] \[AP = 7\]Log in or create a free account to answer this question.