Answer: m(arc DC) = \(121^\circ\)
When two chords intersect inside a circle, each angle formed is half the sum of the arcs intercepted by the angle and its vertically opposite angle:
\[\angle ABE = \frac{1}{2}[m(\text{arc AE}) + m(\text{arc DC})]\] \[108 = \frac{1}{2}[95 + m(\text{arc DC})]\] \[m(\text{arc DC}) = 216^\circ - 95^\circ = 121^\circ\]