Answer: (B) 72
2∠A = 3∠C, so \(\angle A = \frac{3}{2}\angle C\). Opposite angles of a cyclic quadrilateral are supplementary:
\[\frac{3}{2}\angle C + \angle C = 180^\circ\] \[\frac{5}{2}\angle C = 180^\circ,\quad \angle C = 72^\circ\](Then \(\angle A = 108^\circ\); check: \(2 \times 108 = 216 = 3 \times 72\).)