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Answer: Chord PQ is a diameter (6.6 = 2 × 3.3), so the tangents at P and Q are parallel to each other.

Steps of construction:

  1. Draw a circle with centre O and radius 3.3 cm.
  2. Take point P on the circle. With centre P and radius 6.6 cm cut the circle at Q. Draw chord PQ; it passes through O because its length equals the diameter.
  3. Draw line \(l\) through P perpendicular to OP, and line \(m\) through Q perpendicular to OQ.

Observation: both tangents are perpendicular to the same line PQ, so line \(l \parallel\) line \(m\). Tangents at the ends of a diameter are parallel.

Doubtly AI · 24 Oct 2026 AI-verified · Oct 2026 Report
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