Answer: Draw a circle on OP (OP = 7.3 cm) as diameter; it cuts the given circle at A and B. PA and PB are the tangents (each ≈ 6 cm).
Steps of construction:
- Draw a circle with centre O and radius 4.1 cm.
- Mark point P such that OP = 7.3 cm and draw seg OP.
- Draw the perpendicular bisector of seg OP; let it cut OP at M (the midpoint).
- With centre M and radius MO, draw a circle. Name the points where it cuts the given circle as A and B.
- Draw lines PA and PB. These are the required tangents.
Why it works: \(\angle OAP\) and \(\angle OBP\) are angles inscribed in a semicircle (diameter OP), so each is \(90^\circ\). A line perpendicular to a radius at its outer end is a tangent.
Check: each tangent segment \(= \sqrt{7.3^2 - 4.1^2} \approx 6.0\) cm, and the two tangent segments are equal.