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Answer: P(1, 3)

By the section formula, if P divides AB in the ratio m : n = 2 : 3, then

\(P = \left(\dfrac{mx_2 + nx_1}{m + n}, \dfrac{my_2 + ny_1}{m + n}\right)\)

\(x = \dfrac{2(4) + 3(-1)}{2 + 3} = \dfrac{8 - 3}{5} = 1\), \(y = \dfrac{2(-3) + 3(7)}{2 + 3} = \dfrac{-6 + 21}{5} = 3\).

∴ P(1, 3).

Doubtly AI · 24 Oct 2026 AI-verified · Oct 2026 Report
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