Find the slope of the diagonals of a quadrilateral with vertices A(1, 7), B(6, 3), C(0, -3) and D(-3, 3).

Doubtly Asked 24 Oct 2026 Save WhatsApp Report

1 answer

Answer: Slope of AC = 10, slope of BD = 0

Slope \(=\dfrac{y_2-y_1}{x_2-x_1}\).

Diagonal AC: \(\dfrac{-3-7}{0-1}=\dfrac{-10}{-1}=10\).

Diagonal BD: \(\dfrac{3-3}{-3-6}=\dfrac{0}{-9}=0\) (BD is parallel to the X-axis).

Doubtly AI · 24 Oct 2026 AI-verified · Oct 2026 Report

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