Answer: cosθ = 60/61
\(\sin^2\theta+\cos^2\theta=1\)
\[\cos^2\theta=1-\left(\tfrac{11}{61}\right)^2=\tfrac{3721-121}{3721}=\tfrac{3600}{3721}\]
\[\cos\theta=\tfrac{60}{61}\]
(taking θ as an acute angle, so cosθ is positive).
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Doubtly AI
· 24 Oct 2026
AI-verified · Oct 2026
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