Answer: sinθ = 2/√5, cosθ = 1/√5, cosecθ = √5/2, secθ = √5, cotθ = 1/2
\(\cot\theta=\dfrac1{\tan\theta}=\dfrac12\).
\[\sec^2\theta=1+\tan^2\theta=1+4=5\Rightarrow\sec\theta=\sqrt5\]
\(\cos\theta=\dfrac1{\sqrt5}\). Then \(\sin\theta=\tan\theta\cdot\cos\theta=\dfrac2{\sqrt5}\) and \(\csc\theta=\dfrac{\sqrt5}{2}\).
(θ is taken as acute, so all ratios are positive.)