Answer: cosθ = 12/13, sinθ = 5/13, tanθ = 5/12, cosecθ = 13/5, cotθ = 12/5
\(\cos\theta=\dfrac1{\sec\theta}=\dfrac{12}{13}\).
\[\tan^2\theta=\sec^2\theta-1=\tfrac{169-144}{144}=\tfrac{25}{144}\]
So \(\tan\theta=\dfrac5{12}\) and \(\cot\theta=\dfrac{12}5\).
\(\sin\theta=\tan\theta\cdot\cos\theta=\dfrac5{12}\cdot\dfrac{12}{13}=\dfrac5{13}\), so \(\csc\theta=\dfrac{13}5\).