Find the surface area and the volume of a beach ball of diameter 42 cm (spherical).
Find the surface area and the volume of a beach ball shown in the figure.
Figure: a spherical beach ball of diameter 42 cm.
1 answer
Answer: Surface area = 5538.96 cm², volume = 38772.72 cm³ (π = 3.14)
Radius \(r=\dfrac{42}{2}=21\) cm.
\[\text{Surface area}=4\pi r^2=4\times3.14\times441\]
\[=5538.96\ \text{cm}^2\]
\[\text{Volume}=\tfrac43\pi r^3=\tfrac43\times3.14\times9261\]
\[=38772.72\ \text{cm}^3\]
(With \(\pi=\tfrac{22}{7}\): 5544 cm² and 38808 cm³.)
Doubtly AI
· 24 Oct 2026
AI-verified · Oct 2026
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