The circumferences of circular faces of a frustum are 132 cm and 88 cm and its height is 24 cm. To find the curved surface area of the frustum complete the following activity. ( π=22/7 ) circumference ₁=2π r₁=132 , r₁=132/2π=square ; circumference ₂=2π r₂=88 , r₂=88/2π=square ; slant height l=√(h²+(r₁-r₂)²)=√(square²+square²)=square cm; curved surface area =π(r₁+r₂)l=π×square×square=square sq.cm.

Answer: Curved surface area = 2750 cm² 2π r₁=132⇒ r₁=132×7/44=21 cm 2π r₂=88⇒ r₂=88×7/44=14 cm l=√(h²+(r₁-r₂)²)=√(24²+7²) =√(625)=25\ cm CSA=π(r₁+r₂)l=22/7×35×25 =2750\ cm²

The circumferences of circular faces of a frustum are 132 cm and 88 cm and its height is 24 cm. Find the curved surface area of the frustum. (π = 22/7)

The circumferences of circular faces of a frustum are 132 cm and 88 cm and its height is 24 cm. To find the curved surface area of the frustum complete the following activity. (\(\pi=\tfrac{22}{7}\))

circumference\(_1=2\pi r_1=132\), \(r_1=\dfrac{132}{2\pi}=\square\); circumference\(_2=2\pi r_2=88\), \(r_2=\dfrac{88}{2\pi}=\square\); slant height \(l=\sqrt{h^2+(r_1-r_2)^2}=\sqrt{\square^2+\square^2}=\square\) cm; curved surface area \(=\pi(r_1+r_2)l=\pi\times\square\times\square=\square\) sq.cm.

Doubtly Asked 24 Oct 2026 Save WhatsApp Report

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Answer: Curved surface area = 2750 cm²

\(2\pi r_1=132\Rightarrow r_1=\dfrac{132\times7}{44}=21\) cm

\(2\pi r_2=88\Rightarrow r_2=\dfrac{88\times7}{44}=14\) cm

\[l=\sqrt{h^2+(r_1-r_2)^2}=\sqrt{24^2+7^2}\]

\[=\sqrt{625}=25\ \text{cm}\]

\[\text{CSA}=\pi(r_1+r_2)l=\tfrac{22}{7}\times35\times25\]

\[=2750\ \text{cm}^2\]

Doubtly AI · 24 Oct 2026 AI-verified · Oct 2026 Report

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The circumferences of circular faces of a frustum are 132 cm and 88 cm and its height is 24 cm. Find the curved surface area of the frustum. (π = 22/7)

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