Answer: 47.1 cm²
Area of sector \(=\dfrac{\theta}{360}\times\pi r^2\); length of arc \(=\dfrac{\theta}{360}\times2\pi r\).
\[A=\frac{54}{360}\times3.14\times100=\frac{3}{20}\times314=47.1\ \text{cm}^2\]
Answer: 47.1 cm²
Area of sector \(=\dfrac{\theta}{360}\times\pi r^2\); length of arc \(=\dfrac{\theta}{360}\times2\pi r\).
\[A=\frac{54}{360}\times3.14\times100=\frac{3}{20}\times314=47.1\ \text{cm}^2\]
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