In figure 7.33 O is the centre of the sector. ∠ROQ = ∠MON = 60°. OR = 7 cm, and OM = 21 cm. Find the lengths of arc RXQ and arc MYN. ( π=22/7 ) Figure: R lies on seg OM and Q on seg ON; arc RXQ has centre O and radius OR, arc MYN has centre O and radius OM.

Answer: l(arc RXQ) = 22/3 ≈ 7.33 cm, l(arc MYN) = 22 cm Area of sector =θ/360×π r² ; length of arc =θ/360×2π r . l(RXQ)=60/360×2×22/7×7=22/3≈7.33\ cm l(MYN)=60/360×2×22/7×21=22\ cm

O is the centre of the sector. ∠ROQ = ∠MON = 60°. OR = 7 cm, and OM = 21 cm. Find the lengths of arc RXQ and arc MYN. (π = 22/7)

In figure 7.33 O is the centre of the sector. ∠ROQ = ∠MON = 60°. OR = 7 cm, and OM = 21 cm. Find the lengths of arc RXQ and arc MYN. (\(\pi=\tfrac{22}{7}\))

Figure: R lies on seg OM and Q on seg ON; arc RXQ has centre O and radius OR, arc MYN has centre O and radius OM.

Doubtly Asked 24 Oct 2026 Save WhatsApp Report

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Answer: l(arc RXQ) = 22/3 ≈ 7.33 cm, l(arc MYN) = 22 cm

Area of sector \(=\dfrac{\theta}{360}\times\pi r^2\); length of arc \(=\dfrac{\theta}{360}\times2\pi r\).

\[l(RXQ)=\frac{60}{360}\times2\times\frac{22}{7}\times7=\frac{22}{3}\approx7.33\ \text{cm}\]

\[l(MYN)=\frac{60}{360}\times2\times\frac{22}{7}\times21=22\ \text{cm}\]

Doubtly AI · 24 Oct 2026 AI-verified · Oct 2026 Report

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O is the centre of the sector. ∠ROQ = ∠MON = 60°. OR = 7 cm, and OM = 21 cm. Find the lengths of arc RXQ and arc MYN. (π = 22/7)

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