Answer: Minor segment ≈ 20.44 cm², major segment ≈ 686.06 cm²
The triangle formed by the radii and chord PQ is equilateral (central angle 60°).
\[A(\text{sector})=\frac{60}{360}\times3.14\times225=117.75\]
\[A(\Delta)=\frac{\sqrt3}{4}\times225=\frac{1.73\times225}{4}=97.3125\]
\[\text{Minor segment}=117.75-97.3125=20.4375\]
Area of circle \(=3.14\times225=706.5\) cm².
\[\text{Major segment}=706.5-20.4375=686.0625\]
So the segments are about 20.44 cm² and 686.06 cm².