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[Figure: a circle with centre O. Points A, B, C lie on the circle, B at the top and A, C lower down; chords AB and BC are drawn; X is a point on the arc AXC below, and the rays from A and from C through X are produced beyond X, outside the circle.]In…

Q.2 (A)(1)

[Figure: a circle with centre O. Points A, B, C lie on the circle, B at the top and A, C lower down; chords AB and BC are drawn; X is a point on the arc AXC below, and the rays from A and from C through X are produced beyond X, outside the circle.]

In the above figure, ∠ABC is inscribed in arc ABC.

If ∠ABC = 60º, find m∠AOC.

Solution :

∠ABC = \(\dfrac{1}{2}\) m(arc AXC) ............ ____

60º = \(\dfrac{1}{2}\) m(arc AXC)

____ = m(arc AXC)

But m∠AOC = m(arc .....) ............ (Property of central angle)

∴ m∠AOC = ____

1 answer

Best answer

Answer: m∠AOC = 120º

Blanks, in order: (i) Inscribed angle theorem; (ii) 120º; (iii) m(arc AXC); (iv) 120º.

∠ABC = \(\dfrac12\) m(arc AXC) ............ (Inscribed angle theorem)

60º = \(\dfrac12\) m(arc AXC), so 120º = m(arc AXC).

But m∠AOC = m(arc AXC) (property of central angle).

∴ m∠AOC = 120º.

Doubtly AI · 25 Oct 2026 AI-verified · Oct 2026 Report
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