Q.2 (A)(2) If secθ = 25/7 , find the value of tanθ . Solution : 1 + tan² θ = ____ ∴ 1 + tan² θ = ____² ∴ tan² θ = 625/49 – ____ = 625 - 49/49 ∴ tan² θ = 576/49 ∴ tan θ = ____

Answer: tan θ = 24/7 1 + tan² θ = sec² θ = (25/7)² = 625/49 . ∴ tan² θ = 625/49 - 1 = 625 - 49/49 = 576/49 . ∴ tan θ = 24/7 . Blanks in order: sec² θ, 25/7 , 1, 24/7 .

If \(\sec\theta = \dfrac{25}{7}\), find the value of \(\tan\theta\).Solution :1 + tan2 θ = ∴ 1 + tan2 θ = 2∴ tan2 θ = \(\dfrac{625}{49}\) – = \(\dfrac{625 - 49}{49}\)∴ tan2 θ = \(\dfrac{576}{49}\)∴ tan θ =

Q.2 (A)(2) If \(\sec\theta = \dfrac{25}{7}\), find the value of \(\tan\theta\).

Solution :

1 + tan² θ = ____
∴ 1 + tan² θ = ____²
∴ tan² θ = \(\dfrac{625}{49}\) – ____
= \(\dfrac{625 - 49}{49}\)
∴ tan² θ = \(\dfrac{576}{49}\)
∴ tan θ = ____

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Answer: tan θ = \(\dfrac{24}{7}\)

1 + tan² θ = sec² θ = \(\left(\dfrac{25}{7}\right)^2 = \dfrac{625}{49}\).

∴ tan² θ = \(\dfrac{625}{49} - 1 = \dfrac{625 - 49}{49} = \dfrac{576}{49}\).

∴ tan θ = \(\dfrac{24}{7}\).

Blanks in order: sec² θ, \(\dfrac{25}{7}\), 1, \(\dfrac{24}{7}\).

Doubtly AI · 25 Oct 2026 AI-verified · Oct 2026 Report

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If \(\sec\theta = \dfrac{25}{7}\), find the value of \(\tan\theta\).Solution :1 + tan2 θ = ____∴ 1 + tan2 θ = ____2∴ tan2 θ = \(\dfrac{625}{49}\) – ____= \(\dfrac{625 - 49}{49}\)∴ tan2 θ = \(\dfrac{576}{49}\)∴ tan θ = ____

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If \(\sec\theta = \dfrac{25}{7}\), find the value of \(\tan\theta\).Solution :1 + tan2 θ = ∴ 1 + tan2 θ = 2∴ tan2 θ = \(\dfrac{625}{49}\) – = \(\dfrac{625 - 49}{49}\)∴ tan2 θ = \(\dfrac{576}{49}\)∴ tan θ =