Deduce Maxwell’s second equation in differential and integral form.
Q.5 (b) Deduce Maxwell’s second equation in differential and integral form.
Q.5 (b) Deduce Maxwell’s second equation in differential and integral form.
Best answer
Maxwell's second equation is Gauss's law for magnetism.
Integral form: Magnetic field lines are always closed loops, because isolated magnetic poles (monopoles) do not exist. So every line that enters a closed surface also leaves it, and the net magnetic flux through any closed surface is zero:
\[ \boxed{\oint_S\vec B\cdot d\vec S=0} \]
Differential form: Apply Gauss's divergence theorem to the closed surface S enclosing volume V:
\[ \oint_S\vec B\cdot d\vec S=\int_V(\nabla\cdot\vec B)\,dV=0 \]
This holds for any arbitrary volume, so the integrand must itself vanish:
\[ \boxed{\nabla\cdot\vec B=0} \]
Significance: Magnetic monopoles do not exist, and \(\vec B\) is a solenoidal (divergence-free) field. So \(\vec B\) can be written as the curl of a vector potential: \(\vec B=\nabla\times\vec A\), consistent with \(\nabla\cdot(\nabla\times\vec A)=0\). Compare this with Maxwell's first equation, \(\nabla\cdot\vec D=\rho\), for electric charges.
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